< %@LANGUAGE = " VBSCRIPT "  CODEPAGE = " 65001 " % >
< ! -- #include file = " json.asp " -->
< ! -- #include file = " inc/Conn.asp "   -->
< %
response.ContentType = " text/json "
dim  j

' 多重嵌套的JSON,要使用Dictionary才能实现
set  j = new  json
j.toResponse = false
set  r = server.createobject( " scripting.dictionary " )
set  b = server.createobject( " scripting.dictionary " )
set  c = server.createobject( " scripting.dictionary " )
c.add  " x " , 5
c.add  " y " , 6
c.add  " z " , 11
b.add  " event " , " Mouse Click "
b.add  " data " ,c
r.add  " success " , true
r.add  " result " ,b
a = j.toJSON( empty ,r, false )
response.write a
' 记录集转为Json
set  i = new  json
i.toresponse = false
set  rs = server.CreateObject( " adodb.recordset " )
sqlstr = " select top 5 * from producttype "
rs.open sqlstr,conn, 0 , 1
v = i.toJson( " result " ,rs, false )
rs.close
response.write v
% >

面要注意的是:

1,嵌套的JSON是要用DICTIONARY来生成的,其他的方法,我还没有找到

2,最终的结果在输出时,可以用toJson(empty,r,false)这种形式,这样,生成的JSON,就不会类似{var: {var1:'',var2:''}}这种形式,而是直接的:{var1:'',var2:''},这种格式在我们用来处理表单,返回数据时,一定要注意

3,生成JSON的ASP页面,输出格式,解析JSON的JS文件,HTML页面,必须全是UTF-8格式编码,一个环节编码不正确,就会导致接收到的JSON在显示中文时变乱码

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            {
                if(j==t) break;
                sb.append(arr.get(j).toString());
                sb.append(":");
                sb.append("\"");
                sb.append(arr.get(j+1).toString());
                sb.append("\"");
                if(j             }
            sb.append("}");
            if(i ");
        }
        sb.append("
]");
        sb.append("}");
        return sb.toString();
    }
    

}
<%@page imp ort="com.zb.database.util.*,
                com.zb.database.service.*,
                com.zb.database.entity.*, 
                java.util.List"%>
<%
    Json json=new Json();
    UserService user = new UserService();
    List list = user.getUserList();
    Users users;
    json.reSet();
    json.setSuccess(true);
    int j=list.size();
    for (int i=0; i     {
        users = (Users) list.get(i);
        json.addItem("userId",users.getId().toString());
        json.addItem("name",users.getUserName());
        json.addItem("pwd",users.getUserPwd());
        json.addItem("age",users.getUserAge().toString());
        json.addItemOk();
    }
    out.println(json.ToString());
%>